What are the solutions to the equation 3x^2-7x-9=4x^2-4x-9 ?

The solutions to the equation 3x^2-7x-9=4x^2-4x-9 are x=-3,x=0

Find the zeros of 3x^2-7x-9=4x^2-4x-9

The zeros of 3x^2-7x-9=4x^2-4x-9 are x=-3,x=0

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3 x^{2} - 7 x - 9 = 4 x^{2} - 4 x - 9

x = - 3, x = 0

Solution steps

3 x^{2} - 7 x - 9 = 4 x^{2} - 4 x - 9

Move

9

to the left side

3 x^{2} - 7 x = 4 x^{2} - 4 x

Move

4 x

to the left side

3 x^{2} - 3 x = 4 x^{2}

Move

4 x^{2}

to the left side

- x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 3}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 3}{2 ( - 1 )} : - 3

x = \frac{- ( - 3 ) - 3}{2 ( - 1 )} : 0

The solutions to the quadratic equation are:

x = - 3, x = 0

a^{2} - 1

- 3 (6 + 3 x) = - 72

k^{2} + 12 = 0

9 - ∣ 3 (b - 4) - b ∣ \leq 7

x^{2} - x y - 30 y^{2}

What are the solutions to the equation 3x^2-7x-9=4x^2-4x-9 ?
The solutions to the equation 3x^2-7x-9=4x^2-4x-9 are x=-3,x=0
Find the zeros of 3x^2-7x-9=4x^2-4x-9
The zeros of 3x^2-7x-9=4x^2-4x-9 are x=-3,x=0