What is factor 16x^4-1 ?

The solution to factor 16x^4-1 is (4x^2+1)(2x+1)(2x-1)

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factor 16x^4-1

factor

16 x^{4} - 1

(4 x^{2} + 1) (2 x + 1) (2 x - 1)

Solution steps

16 x^{4} - 1

Apply exponent rules

= (4 x^{2})^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 x^{2})^{2} - 1^{2} = (4 x^{2} + 1) (4 x^{2} - 1)

= (4 x^{2} + 1) (4 x^{2} - 1)

Factor

4 x^{2} - 1 : (2 x + 1) (2 x - 1)

= (4 x^{2} + 1) (2 x + 1) (2 x - 1)

2 x - 3 < x + 4 < 3 x - 2

7 x^{2} + 14 x = 0

ab - 2 a - 5 b + 10

3 - 81

(\frac{8}{5})^{- 1}