What are the solutions to the equation (x-2)(5x+1)=0 ?

The solutions to the equation (x-2)(5x+1)=0 are x=2,x=-1/5

Find the zeros of (x-2)(5x+1)=0

The zeros of (x-2)(5x+1)=0 are x=2,x=-1/5

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(x - 2) (5 x + 1) = 0

x = 2, x = - \frac{1}{5}

Decimal Notation

x = 2, x = - 0.2

Solution steps

(x - 2) (5 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 5 x + 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

5 x + 1 = 0 : x = - \frac{1}{5}

The solutions to the quadratic equation are:

x = 2, x = - \frac{1}{5}

2 x - 2 (x - 1) + 5 = 4 - 3 (x + 1)

12 x^{2} - 5 x - 7

5 x^{2} - 4 x + 1 = 0

\frac{3}{10} \cdot \frac{2}{9}

(x - 2)^{2} \leq x^{2} + 1

What are the solutions to the equation (x-2)(5x+1)=0 ?
The solutions to the equation (x-2)(5x+1)=0 are x=2,x=-1/5
Find the zeros of (x-2)(5x+1)=0
The zeros of (x-2)(5x+1)=0 are x=2,x=-1/5