What are the solutions to the equation 5x^2-5x-6=0 ?

The solutions to the equation 5x^2-5x-6=0 are x=(5+sqrt(145))/(10),x=(5-sqrt(145))/(10)

Find the zeros of 5x^2-5x-6=0

The zeros of 5x^2-5x-6=0 are x=(5+sqrt(145))/(10),x=(5-sqrt(145))/(10)

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5 x^{2} - 5 x - 6 = 0

x = \frac{5 + 145}{10}, x = \frac{5 - 145}{10}

Decimal Notation

x = 1.70415 \dots, x = - 0.70415 \dots

Solution steps

5 x^{2} - 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

(- 5)^{2} - 4 \cdot 5 (- 6) = 145

x_{1, 2} = \frac{- ( - 5 ) \pm 145}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 145}{2 \cdot 5}, x_{2} = \frac{- ( - 5 ) - 145}{2 \cdot 5}

x = \frac{- ( - 5 ) + 145}{2 \cdot 5} : \frac{5 + 145}{10}

x = \frac{- ( - 5 ) - 145}{2 \cdot 5} : \frac{5 - 145}{10}

The solutions to the quadratic equation are:

x = \frac{5 + 145}{10}, x = \frac{5 - 145}{10}

\frac{1}{3 ^{- 1}}

\frac{3}{8} + 2

8 x^{2} - 3 = 2

\frac{r}{- 6} + 5 < 7

(3 x + 2)^{2} = 3

What are the solutions to the equation 5x^2-5x-6=0 ?
The solutions to the equation 5x^2-5x-6=0 are x=(5+sqrt(145))/(10),x=(5-sqrt(145))/(10)
Find the zeros of 5x^2-5x-6=0
The zeros of 5x^2-5x-6=0 are x=(5+sqrt(145))/(10),x=(5-sqrt(145))/(10)