What is (k^3-7k+2)-(k^2-12) ?

The solution to (k^3-7k+2)-(k^2-12) is k^3-k^2-7k+14

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simplify (k^3-7k+2)-(k^2-12)

simplify

(k^{3} - 7 k + 2) - (k^{2} - 12)

k^{3} - k^{2} - 7 k + 14

Solution steps

(k^{3} - 7 k + 2) - (k^{2} - 12)

Apply rule:

(a) = a

(k^{3} - 7 k + 2) = k^{3} - 7 k + 2

= k^{3} - 7 k + 2 - (k^{2} - 12)

Apply the distributive law:

- (a - b) = - a + b

- (k^{2} - 12) = - k^{2} + 12

= k^{3} - 7 k + 2 - k^{2} + 12

Group like terms

= k^{3} - k^{2} - 7 k + 2 + 12

Add the numbers:

2 + 12 = 14

= k^{3} - k^{2} - 7 k + 14

∣ x - 4 ∣ > 2

\frac{1 - 8 i}{- 2 + 3 i}

- 4 d^{3} + 28 d^{2} - 4 d

x^{2} = 0

4 x - 3 = 6 x + 2

What is (k^3-7k+2)-(k^2-12) ?
The solution to (k^3-7k+2)-(k^2-12) is k^3-k^2-7k+14