What is the answer to (x+9)(x-3)=(x+1)^2 ?

The answer to (x+9)(x-3)=(x+1)^2 is x=7

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(x+9)(x-3)=(x+1)^2

(x + 9) (x - 3) = (x + 1)^{2}

x = 7

Solution steps

(x + 9) (x - 3) = (x + 1)^{2}

Expand

(x + 9) (x - 3) : x^{2} + 6 x - 27

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

x^{2} + 6 x - 27 = x^{2} + 2 x + 1

Move

27

to the right side

x^{2} + 6 x = x^{2} + 2 x + 28

Subtract

x^{2} + 2 x

from both sides

x^{2} + 6 x - (x^{2} + 2 x) = x^{2} + 2 x + 28 - (x^{2} + 2 x)

Simplify

4 x = 28

Divide both sides by

4

x = 7

(- \frac{27}{125})^{\frac{- 2}{3}}

c + 7 = 5 c - (3 + 4 c)

\frac{x}{12} + 3 \leq 7

∣ x + 7 ∣ \geq 2

(\frac{1}{7})^{- 4}

What is the answer to (x+9)(x-3)=(x+1)^2 ?
The answer to (x+9)(x-3)=(x+1)^2 is x=7
Solve for x: (x+9)(x-3)=(x+1)^2
The solution is x=7