What are the solutions to the equation 4(x-5)^2-50=2 ?

The solutions to the equation 4(x-5)^2-50=2 are x=sqrt(13)+5,x=-sqrt(13)+5

Find the zeros of 4(x-5)^2-50=2

The zeros of 4(x-5)^2-50=2 are x=sqrt(13)+5,x=-sqrt(13)+5

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4 (x - 5)^{2} - 50 = 2

x = 13 + 5, x = - 13 + 5

Decimal Notation

x = 8.60555 \dots, x = 1.39444 \dots

Solution steps

4 (x - 5)^{2} - 50 = 2

Move

50

to the right side

4 (x - 5)^{2} = 52

Divide both sides by

4

(x - 5)^{2} = 13

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 13 : x = 13 + 5

Solve

x - 5 = - 13 : x = - 13 + 5

The solutions to the quadratic equation are:

x = 13 + 5, x = - 13 + 5

8 e + 3 (5 - e) = 10

- \frac{x}{3} + 6 - 5 = 0

- 4 x \geq 6

x^{2} + 5 x y + 6 y^{2}

3 x^{2} - 11 x + 8 = 0

What are the solutions to the equation 4(x-5)^2-50=2 ?
The solutions to the equation 4(x-5)^2-50=2 are x=sqrt(13)+5,x=-sqrt(13)+5
Find the zeros of 4(x-5)^2-50=2
The zeros of 4(x-5)^2-50=2 are x=sqrt(13)+5,x=-sqrt(13)+5