What are the solutions to the equation 6x^2+72x+120=0 ?

The solutions to the equation 6x^2+72x+120=0 are x=-2,x=-10

Find the zeros of 6x^2+72x+120=0

The zeros of 6x^2+72x+120=0 are x=-2,x=-10

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6 x^{2} + 72 x + 120 = 0

x = - 2, x = - 10

Solution steps

6 x^{2} + 72 x + 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 72 \pm 7 2 ^{2} - 4 \cdot 6 \cdot 120}{2 \cdot 6}

7 2^{2} - 4 \cdot 6 \cdot 120 = 48

x_{1, 2} = \frac{- 72 \pm 48}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 72 + 48}{2 \cdot 6}, x_{2} = \frac{- 72 - 48}{2 \cdot 6}

x = \frac{- 72 + 48}{2 \cdot 6} : - 2

x = \frac{- 72 - 48}{2 \cdot 6} : - 10

The solutions to the quadratic equation are:

x = - 2, x = - 10

- 2 (3) + 2

\frac{6}{7} - \frac{2}{3}

(123)^{2}

3 x^{2} - 2 x - 14 = 0

\frac{x + 4}{x - 2} - 2 \leq 0

What are the solutions to the equation 6x^2+72x+120=0 ?
The solutions to the equation 6x^2+72x+120=0 are x=-2,x=-10
Find the zeros of 6x^2+72x+120=0
The zeros of 6x^2+72x+120=0 are x=-2,x=-10