What are the solutions to the equation 49w^2-25=0 ?

The solutions to the equation 49w^2-25=0 are w= 5/7 ,w=-5/7

Find the zeros of 49w^2-25=0

The zeros of 49w^2-25=0 are w= 5/7 ,w=-5/7

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49 w^{2} - 25 = 0

w = \frac{5}{7}, w = - \frac{5}{7}

Solution steps

49 w^{2} - 25 = 0

Move

25

to the right side

49 w^{2} = 25

Divide both sides by

49

w^{2} = \frac{25}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

w = \frac{25}{49}, w = - \frac{25}{49}

\frac{25}{49} = \frac{5}{7}

- \frac{25}{49} = - \frac{5}{7}

w = \frac{5}{7}, w = - \frac{5}{7}

(\frac{2}{3})^{3} + 1

2 x^{2} = 2 x + 4

8 x + 8

1.2 n + 3.4 \leq 7.6

- 24 + 6 x = - 6

What are the solutions to the equation 49w^2-25=0 ?
The solutions to the equation 49w^2-25=0 are w= 5/7 ,w=-5/7
Find the zeros of 49w^2-25=0
The zeros of 49w^2-25=0 are w= 5/7 ,w=-5/7