What are the solutions to the equation 2p^2-3p-2=0 ?

The solutions to the equation 2p^2-3p-2=0 are p=2,p=-1/2

Find the zeros of 2p^2-3p-2=0

The zeros of 2p^2-3p-2=0 are p=2,p=-1/2

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2 p^{2} - 3 p - 2 = 0

p = 2, p = - \frac{1}{2}

Decimal Notation

p = 2, p = - 0.5

Solution steps

2 p^{2} - 3 p - 2 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 2) = 5

p_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- ( - 3 ) + 5}{2 \cdot 2}, p_{2} = \frac{- ( - 3 ) - 5}{2 \cdot 2}

p = \frac{- ( - 3 ) + 5}{2 \cdot 2} : 2

p = \frac{- ( - 3 ) - 5}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

p = 2, p = - \frac{1}{2}

2 x^{2} + x + 6 = 7

2500

\frac{10}{( - \frac{5}{8} )}

x - 5 \geq 9

x^{3} - 2 x^{2} + 26 x

What are the solutions to the equation 2p^2-3p-2=0 ?
The solutions to the equation 2p^2-3p-2=0 are p=2,p=-1/2
Find the zeros of 2p^2-3p-2=0
The zeros of 2p^2-3p-2=0 are p=2,p=-1/2