What are the solutions to the equation y(y+1)-4=0 ?

The solutions to the equation y(y+1)-4=0 are y=(-1+sqrt(17))/2 ,y=(-1-sqrt(17))/2

Find the zeros of y(y+1)-4=0

The zeros of y(y+1)-4=0 are y=(-1+sqrt(17))/2 ,y=(-1-sqrt(17))/2

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y (y + 1) - 4 = 0

y = \frac{- 1 + 17}{2}, y = \frac{- 1 - 17}{2}

Decimal Notation

y = 1.56155 \dots, y = - 2.56155 \dots

Solution steps

y (y + 1) - 4 = 0

Expand

y (y + 1) - 4 : y^{2} + y - 4

y^{2} + y - 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 4) = 17

y_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 1 + 17}{2 \cdot 1}, y_{2} = \frac{- 1 - 17}{2 \cdot 1}

y = \frac{- 1 + 17}{2 \cdot 1} : \frac{- 1 + 17}{2}

y = \frac{- 1 - 17}{2 \cdot 1} : \frac{- 1 - 17}{2}

The solutions to the quadratic equation are:

y = \frac{- 1 + 17}{2}, y = \frac{- 1 - 17}{2}

2 (2 q + 1.5) = 18 - q

3 x - 3 > 34

11 x - 32 = 31 + 8 x

9 a + 6

What are the solutions to the equation y(y+1)-4=0 ?
The solutions to the equation y(y+1)-4=0 are y=(-1+sqrt(17))/2 ,y=(-1-sqrt(17))/2
Find the zeros of y(y+1)-4=0
The zeros of y(y+1)-4=0 are y=(-1+sqrt(17))/2 ,y=(-1-sqrt(17))/2