What are the solutions to the equation 10a^2+20a+10=0 ?

The solutions to the equation 10a^2+20a+10=0 are a=-1

Find the zeros of 10a^2+20a+10=0

The zeros of 10a^2+20a+10=0 are a=-1

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10 a^{2} + 20 a + 10 = 0

a = - 1

Solution steps

10 a^{2} + 20 a + 10 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

2 0^{2} - 4 \cdot 10 \cdot 10 = 0

a_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 10}

a = \frac{- 20}{2 \cdot 10}

\frac{- 20}{2 \cdot 10} = - 1

a = - 1

The solution to the quadratic equation is:

a = - 1

(6 + 2 - 12) (6 - 2) + 72

\frac{2 x - 2}{x + 1} \leq 1

2 x - 1 = 6

y^{- \frac{11}{10}}

\frac{2}{3} x + 3 = \frac{2}{7}

What are the solutions to the equation 10a^2+20a+10=0 ?
The solutions to the equation 10a^2+20a+10=0 are a=-1
Find the zeros of 10a^2+20a+10=0
The zeros of 10a^2+20a+10=0 are a=-1