What is ((2t^5u^3)/(4t^4))^3 ?

The solution to ((2t^5u^3)/(4t^4))^3 is (t^3u^9)/8

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simplify ((2t^5u^3)/(4t^4))^3

simplify

(\frac{2 t ^{5} u ^{3}}{4 t ^{4}})^{3}

\frac{t ^{3} u ^{9}}{8}

Solution steps

(\frac{2 t ^{5} u ^{3}}{4 t ^{4}})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 t ^{5} u ^{3} ) ^{3}}{( 4 t ^{4} ) ^{3}}

Simplify

(2 t^{5} u^{3})^{3} : 8 t^{15} u^{9}

= \frac{8 t ^{15} u ^{9}}{( 4 t ^{4} ) ^{3}}

Simplify

(4 t^{4})^{3} : 64 t^{12}

= \frac{8 t ^{15} u ^{9}}{64 t ^{12}}

Cancel the common factor:

8

= \frac{t ^{15} u ^{9}}{8 t ^{12}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{t ^{15}}{t ^{12}} = t^{15 - 12}

= \frac{u ^{9} t ^{15 - 12}}{8}

Subtract the numbers:

15 - 12 = 3

= \frac{t ^{3} u ^{9}}{8}

\frac{1}{4} x - 2 = - 6 + \frac{5}{12} x

6 x y^{2} (3 y - x) - 3 x^{2} (x - 3 y)^{2}

(\frac{27}{8})^{- \frac{2}{3}}

1 + 3 i

4 c = 34

What is ((2t^5u^3)/(4t^4))^3 ?
The solution to ((2t^5u^3)/(4t^4))^3 is (t^3u^9)/8