What are the solutions to the equation t^2-7=-18 ?

The solutions to the equation t^2-7=-18 are t=sqrt(11)i,t=-sqrt(11)i

Find the zeros of t^2-7=-18

The zeros of t^2-7=-18 are t=sqrt(11)i,t=-sqrt(11)i

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t^{2} - 7 = - 18

t = 11 i, t = - 11 i

Solution steps

t^{2} - 7 = - 18

Move

7

to the right side

t^{2} = - 11

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = - 11, t = - - 11

- 11 = 11 i

- - 11 = - 11 i

t = 11 i, t = - 11 i

x^{- \frac{1}{6}}

2 x + \frac{1}{x} - 3 \geq 2

x^{2} - 3 (x^{2} - 1) = x (x - 1)

(x - 17)^{2} = 12

4 n + 2 = 5 n + 6

What are the solutions to the equation t^2-7=-18 ?
The solutions to the equation t^2-7=-18 are t=sqrt(11)i,t=-sqrt(11)i
Find the zeros of t^2-7=-18
The zeros of t^2-7=-18 are t=sqrt(11)i,t=-sqrt(11)i