What are the solutions to the equation 3x^2+27x=0 ?

The solutions to the equation 3x^2+27x=0 are x=0,x=-9

Find the zeros of 3x^2+27x=0

The zeros of 3x^2+27x=0 are x=0,x=-9

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3 x^{2} + 27 x = 0

x = 0, x = - 9

Solution steps

3 x^{2} + 27 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 27 \pm 2 7 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

2 7^{2} - 4 \cdot 3 \cdot 0 = 27

x_{1, 2} = \frac{- 27 \pm 27}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 27 + 27}{2 \cdot 3}, x_{2} = \frac{- 27 - 27}{2 \cdot 3}

x = \frac{- 27 + 27}{2 \cdot 3} : 0

x = \frac{- 27 - 27}{2 \cdot 3} : - 9

The solutions to the quadratic equation are:

x = 0, x = - 9

- 12 < x < - 3

- \frac{2}{3} + 4

- 8 x + 3 \geq 27 - 13 x + 5 \geq 57

5 x^{2} + 17 x + 6

(y^{\frac{2}{3}})^{2}

What are the solutions to the equation 3x^2+27x=0 ?
The solutions to the equation 3x^2+27x=0 are x=0,x=-9
Find the zeros of 3x^2+27x=0
The zeros of 3x^2+27x=0 are x=0,x=-9