What are the solutions to the equation x^2+(1/3)^2=1^2 ?

The solutions to the equation x^2+(1/3)^2=1^2 are x=(2sqrt(2))/3 ,x=-(2sqrt(2))/3

Find the zeros of x^2+(1/3)^2=1^2

The zeros of x^2+(1/3)^2=1^2 are x=(2sqrt(2))/3 ,x=-(2sqrt(2))/3

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x^{2} + (\frac{1}{3})^{2} = 1^{2}

x = \frac{2 2}{3}, x = - \frac{2 2}{3}

Decimal Notation

x = 0.94280 \dots, x = - 0.94280 \dots

Solution steps

x^{2} + (\frac{1}{3})^{2} = 1^{2}

Expand

x^{2} + (\frac{1}{3})^{2} : x^{2} + \frac{1}{9}

Expand

1^{2} : 1

x^{2} + \frac{1}{9} = 1

Move

\frac{1}{9}

to the right side

x^{2} = 1 - \frac{1}{9}

Simplify

1 - \frac{1}{9} : \frac{8}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{8}{9}, x = - \frac{8}{9}

\frac{8}{9} = \frac{2 2}{3}

- \frac{8}{9} = - \frac{2 2}{3}

x = \frac{2 2}{3}, x = - \frac{2 2}{3}

\frac{( x + 7 ) ( x - 9 )}{x + 5} \leq 0

- \frac{4}{5} + 1

2 ∣ 2 x - 1 ∣ + 12 > 22

- 40 ab c - 12 a c

- 6 - 54

What are the solutions to the equation x^2+(1/3)^2=1^2 ?
The solutions to the equation x^2+(1/3)^2=1^2 are x=(2sqrt(2))/3 ,x=-(2sqrt(2))/3
Find the zeros of x^2+(1/3)^2=1^2
The zeros of x^2+(1/3)^2=1^2 are x=(2sqrt(2))/3 ,x=-(2sqrt(2))/3