What are the solutions to the equation n^2-10n+22=-2 ?

The solutions to the equation n^2-10n+22=-2 are n=6,n=4

Find the zeros of n^2-10n+22=-2

The zeros of n^2-10n+22=-2 are n=6,n=4

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n^{2} - 10 n + 22 = - 2

n = 6, n = 4

Solution steps

n^{2} - 10 n + 22 = - 2

Move

2

to the left side

n^{2} - 10 n + 24 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 24 = 2

n_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 1}, n_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 1}

n = \frac{- ( - 10 ) + 2}{2 \cdot 1} : 6

n = \frac{- ( - 10 ) - 2}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

n = 6, n = 4

\frac{( x + 4 )}{25} \geq (\frac{( x - 3 )}{10}) + (\frac{2}{50})

(15)^{2}

4 \geq - \frac{t}{2}

x^{2} - 5 x = 4

(3 - 5 i) (- 2 + 4 i)

What are the solutions to the equation n^2-10n+22=-2 ?
The solutions to the equation n^2-10n+22=-2 are n=6,n=4
Find the zeros of n^2-10n+22=-2
The zeros of n^2-10n+22=-2 are n=6,n=4