What are the solutions to the equation x^2+x-7=0 ?

The solutions to the equation x^2+x-7=0 are x=(-1+sqrt(29))/2 ,x=(-1-sqrt(29))/2

Find the zeros of x^2+x-7=0

The zeros of x^2+x-7=0 are x=(-1+sqrt(29))/2 ,x=(-1-sqrt(29))/2

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x^{2} + x - 7 = 0

x = \frac{- 1 + 29}{2}, x = \frac{- 1 - 29}{2}

Solution steps

x^{2} + x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 7) = 29

x_{1, 2} = \frac{- 1 \pm 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 29}{2 \cdot 1}, x_{2} = \frac{- 1 - 29}{2 \cdot 1}

x = \frac{- 1 + 29}{2 \cdot 1} : \frac{- 1 + 29}{2}

x = \frac{- 1 - 29}{2 \cdot 1} : \frac{- 1 - 29}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 29}{2}, x = \frac{- 1 - 29}{2}

\frac{x}{6} - \frac{x - 2}{2} = \frac{x - 13}{9}

lo g_{256} (4)

6 x^{2} - 6 x + 3

2 x^{2} - 12 x + 36

What are the solutions to the equation x^2+x-7=0 ?
The solutions to the equation x^2+x-7=0 are x=(-1+sqrt(29))/2 ,x=(-1-sqrt(29))/2
Find the zeros of x^2+x-7=0
The zeros of x^2+x-7=0 are x=(-1+sqrt(29))/2 ,x=(-1-sqrt(29))/2