What are the solutions to the equation x^2+6x+50=0 ?

The solutions to the equation x^2+6x+50=0 are x=-3+sqrt(41)i,x=-3-sqrt(41)i

Find the zeros of x^2+6x+50=0

The zeros of x^2+6x+50=0 are x=-3+sqrt(41)i,x=-3-sqrt(41)i

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x^{2} + 6 x + 50 = 0

x = - 3 + 41 i, x = - 3 - 41 i

Solution steps

x^{2} + 6 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 50 : 241 i

x_{1, 2} = \frac{- 6 \pm 2 41 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 41 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 41 i}{2 \cdot 1}

x = \frac{- 6 + 2 41 i}{2 \cdot 1} : - 3 + 41 i

x = \frac{- 6 - 2 41 i}{2 \cdot 1} : - 3 - 41 i

The solutions to the quadratic equation are:

x = - 3 + 41 i, x = - 3 - 41 i

2 x^{3} > - 8 x^{2}

8.99 \cdot 1 0^{9} \cdot \frac{2 \cdot 11 \cdot 1 0 ^{- 6}}{5}

3 x + 17 + 5 x = 7 x + 10

6 x^{2} - 10 x y + 6 y^{2}

2 m^{2} + 17 m + 8

What are the solutions to the equation x^2+6x+50=0 ?
The solutions to the equation x^2+6x+50=0 are x=-3+sqrt(41)i,x=-3-sqrt(41)i
Find the zeros of x^2+6x+50=0
The zeros of x^2+6x+50=0 are x=-3+sqrt(41)i,x=-3-sqrt(41)i