What are the solutions to the equation 5x^2+14x=3 ?

The solutions to the equation 5x^2+14x=3 are x= 1/5 ,x=-3

Find the zeros of 5x^2+14x=3

The zeros of 5x^2+14x=3 are x= 1/5 ,x=-3

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5 x^{2} + 14 x = 3

x = \frac{1}{5}, x = - 3

Solution steps

5 x^{2} + 14 x = 3

Move

3

to the left side

5 x^{2} + 14 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

1 4^{2} - 4 \cdot 5 (- 3) = 16

x_{1, 2} = \frac{- 14 \pm 16}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 14 + 16}{2 \cdot 5}, x_{2} = \frac{- 14 - 16}{2 \cdot 5}

x = \frac{- 14 + 16}{2 \cdot 5} : \frac{1}{5}

x = \frac{- 14 - 16}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - 3

4 ∣ n ∣ - 19 = 13

z^{2} + 36 = 13 z

- (6)^{- 1}

5 ((- 7) + 9) \leq 10

4 x + (- 6) = 10

What are the solutions to the equation 5x^2+14x=3 ?
The solutions to the equation 5x^2+14x=3 are x= 1/5 ,x=-3
Find the zeros of 5x^2+14x=3
The zeros of 5x^2+14x=3 are x= 1/5 ,x=-3