What are the solutions to the equation x^2+10x=-9 ?

The solutions to the equation x^2+10x=-9 are x=-1,x=-9

Find the zeros of x^2+10x=-9

The zeros of x^2+10x=-9 are x=-1,x=-9

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x^{2} + 10 x = - 9

x = - 1, x = - 9

Solution steps

x^{2} + 10 x = - 9

Move

9

to the left side

x^{2} + 10 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 9 = 8

x_{1, 2} = \frac{- 10 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 8}{2 \cdot 1}, x_{2} = \frac{- 10 - 8}{2 \cdot 1}

x = \frac{- 10 + 8}{2 \cdot 1} : - 1

x = \frac{- 10 - 8}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = - 1, x = - 9

x^{2} + 12 = 12

x + 8 = 5

\frac{x - 2}{x + 3} > - 2

x^{2} + 21 x + 20

3 w + 3 \geq 21

What are the solutions to the equation x^2+10x=-9 ?
The solutions to the equation x^2+10x=-9 are x=-1,x=-9
Find the zeros of x^2+10x=-9
The zeros of x^2+10x=-9 are x=-1,x=-9