What are the solutions to the equation x^2-22x-23=0 ?

The solutions to the equation x^2-22x-23=0 are x=23,x=-1

Find the zeros of x^2-22x-23=0

The zeros of x^2-22x-23=0 are x=23,x=-1

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x^{2} - 22 x - 23 = 0

x = 23, x = - 1

Solution steps

x^{2} - 22 x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 1 \cdot ( - 23 )}{2 \cdot 1}

(- 22)^{2} - 4 \cdot 1 \cdot (- 23) = 24

x_{1, 2} = \frac{- ( - 22 ) \pm 24}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 24}{2 \cdot 1}, x_{2} = \frac{- ( - 22 ) - 24}{2 \cdot 1}

x = \frac{- ( - 22 ) + 24}{2 \cdot 1} : 23

x = \frac{- ( - 22 ) - 24}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 23, x = - 1

\frac{15 !}{4 ! ( 15 - 4 ) !}

X^{2} + 8 X - 128 = 0

x^{3} + x^{2} + 9 x + 9

\frac{17}{20} = t + (- \frac{13}{20})

\frac{2}{4}

What are the solutions to the equation x^2-22x-23=0 ?
The solutions to the equation x^2-22x-23=0 are x=23,x=-1
Find the zeros of x^2-22x-23=0
The zeros of x^2-22x-23=0 are x=23,x=-1