What are the solutions to the equation x^2+10x-7=0 ?

The solutions to the equation x^2+10x-7=0 are x=-5+4sqrt(2),x=-5-4sqrt(2)

Find the zeros of x^2+10x-7=0

The zeros of x^2+10x-7=0 are x=-5+4sqrt(2),x=-5-4sqrt(2)

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x^{2} + 10 x - 7 = 0

x = - 5 + 42, x = - 5 - 42

Solution steps

x^{2} + 10 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 7) = 82

x_{1, 2} = \frac{- 10 \pm 8 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 8 2}{2 \cdot 1}, x_{2} = \frac{- 10 - 8 2}{2 \cdot 1}

x = \frac{- 10 + 8 2}{2 \cdot 1} : - 5 + 42

x = \frac{- 10 - 8 2}{2 \cdot 1} : - 5 - 42

The solutions to the quadratic equation are:

x = - 5 + 42, x = - 5 - 42

4 x - 32

2 x^{2} + 7 x - 4 = 0

6 x = 22

7 (x + 5) = 77

What are the solutions to the equation x^2+10x-7=0 ?
The solutions to the equation x^2+10x-7=0 are x=-5+4sqrt(2),x=-5-4sqrt(2)
Find the zeros of x^2+10x-7=0
The zeros of x^2+10x-7=0 are x=-5+4sqrt(2),x=-5-4sqrt(2)