What are the solutions to the equation (3x+4)^2=9 ?

The solutions to the equation (3x+4)^2=9 are x=-1/3 ,x=-7/3

Find the zeros of (3x+4)^2=9

The zeros of (3x+4)^2=9 are x=-1/3 ,x=-7/3

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(3 x + 4)^{2} = 9

x = - \frac{1}{3}, x = - \frac{7}{3}

Solution steps

(3 x + 4)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 4 = 9 : x = - \frac{1}{3}

Solve

3 x + 4 = - 9 : x = - \frac{7}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - \frac{7}{3}

8 x - 6 > - 62

2 (a - 5) = a + 2.54

- \frac{1}{3} (p + 9) \leq 4

- \frac{2}{3} + \frac{3}{4} (\frac{7}{2})

What are the solutions to the equation (3x+4)^2=9 ?
The solutions to the equation (3x+4)^2=9 are x=-1/3 ,x=-7/3
Find the zeros of (3x+4)^2=9
The zeros of (3x+4)^2=9 are x=-1/3 ,x=-7/3