What is factor 8x^6+729 ?

The solution to factor 8x^6+729 is (2x^2+9)(4x^4-18x^2+81)

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factor 8x^6+729

factor

8 x^{6} + 729

(2 x^{2} + 9) (4 x^{4} - 18 x^{2} + 81)

Solution steps

8 x^{6} + 729

Apply exponent rules

= (2 x^{2})^{3} + 9^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(2 x^{2})^{3} + 9^{3} = (2 x^{2} + 9) (2^{2} x^{4} - 9 \cdot 2 x^{2} + 9^{2})

= (2 x^{2} + 9) (2^{2} x^{4} - 9 \cdot 2 x^{2} + 9^{2})

Simplify

(2 x^{2} + 9) (2^{2} x^{4} - 9 \cdot 2 x^{2} + 9^{2}) : (2 x^{2} + 9) (4 x^{4} - 18 x^{2} + 81)

= (2 x^{2} + 9) (4 x^{4} - 18 x^{2} + 81)

x (x + 3) (x - 4) \leq 0

\frac{( n + 1 ) !}{n !}

2 = \frac{x - 21.4}{5.1}

- - 24 (6 - - 3)

x + 5 \leq 8

What is factor 8x^6+729 ?
The solution to factor 8x^6+729 is (2x^2+9)(4x^4-18x^2+81)