What is (n-2)/(n-3)-5/(n+2) ?

The solution to (n-2)/(n-3)-5/(n+2) is (n^2-5n+11)/((n-3)(n+2))

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simplify (n-2)/(n-3)-5/(n+2)

simplify

\frac{n - 2}{n - 3} - \frac{5}{n + 2}

\frac{n ^{2} - 5 n + 11}{( n - 3 ) ( n + 2 )}

Solution steps

\frac{n - 2}{n - 3} - \frac{5}{n + 2}

Least Common Multiplier of

n - 3, n + 2 : (n - 3) (n + 2)

Adjust Fractions based on the LCM

= \frac{( n - 2 ) ( n + 2 )}{( n - 3 ) ( n + 2 )} - \frac{5 ( n - 3 )}{( n - 3 ) ( n + 2 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{( n - 2 ) ( n + 2 ) - 5 ( n - 3 )}{( n - 3 ) ( n + 2 )}

Simplify

(n - 2) (n + 2) - 5 (n - 3) : n^{2} - 5 n + 11

= \frac{n ^{2} - 5 n + 11}{( n - 3 ) ( n + 2 )}

(2 a + 6 b) (6 b - 2 a) - (2 a + 6 b)^{2}

2 \times (2)

x^{3} \geq 4 x

t, t x = x^{B}

\frac{3 t}{4} - \frac{t}{2} = 1

What is (n-2)/(n-3)-5/(n+2) ?
The solution to (n-2)/(n-3)-5/(n+2) is (n^2-5n+11)/((n-3)(n+2))