What are the solutions to the equation x^2+15x+30=3x-2 ?

The solutions to the equation x^2+15x+30=3x-2 are x=-4,x=-8

Find the zeros of x^2+15x+30=3x-2

The zeros of x^2+15x+30=3x-2 are x=-4,x=-8

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x^{2} + 15 x + 30 = 3 x - 2

x = - 4, x = - 8

Solution steps

x^{2} + 15 x + 30 = 3 x - 2

Move

2

to the left side

x^{2} + 15 x + 32 = 3 x

Move

3 x

to the left side

x^{2} + 12 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 32 = 4

x_{1, 2} = \frac{- 12 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 4}{2 \cdot 1}, x_{2} = \frac{- 12 - 4}{2 \cdot 1}

x = \frac{- 12 + 4}{2 \cdot 1} : - 4

x = \frac{- 12 - 4}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 4, x = - 8

10 \cdot \frac{π}{180}

\frac{4}{\frac{1}{4}}

\frac{5}{6} + \frac{7}{9} + \frac{4}{3}

(1 + 2)^{3}

(\frac{1}{2})^{x - 1} > (\frac{1}{4})^{2}

What are the solutions to the equation x^2+15x+30=3x-2 ?
The solutions to the equation x^2+15x+30=3x-2 are x=-4,x=-8
Find the zeros of x^2+15x+30=3x-2
The zeros of x^2+15x+30=3x-2 are x=-4,x=-8