What are the solutions to the equation 80x^2+23x-9=0 ?

The solutions to the equation 80x^2+23x-9=0 are x=(-23+sqrt(3409))/(160),x=(-23-sqrt(3409))/(160)

Find the zeros of 80x^2+23x-9=0

The zeros of 80x^2+23x-9=0 are x=(-23+sqrt(3409))/(160),x=(-23-sqrt(3409))/(160)

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80 x^{2} + 23 x - 9 = 0

x = \frac{- 23 + 3409}{160}, x = \frac{- 23 - 3409}{160}

Solution steps

80 x^{2} + 23 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 80 ( - 9 )}{2 \cdot 80}

2 3^{2} - 4 \cdot 80 (- 9) = 3409

x_{1, 2} = \frac{- 23 \pm 3409}{2 \cdot 80}

Separate the solutions

x_{1} = \frac{- 23 + 3409}{2 \cdot 80}, x_{2} = \frac{- 23 - 3409}{2 \cdot 80}

x = \frac{- 23 + 3409}{2 \cdot 80} : \frac{- 23 + 3409}{160}

x = \frac{- 23 - 3409}{2 \cdot 80} : \frac{- 23 - 3409}{160}

The solutions to the quadratic equation are:

x = \frac{- 23 + 3409}{160}, x = \frac{- 23 - 3409}{160}

x^{3} + y^{3} + 2 x y (x + y)

28

2 (1 + 2 x) - 5 (4 - 2 x) = 14

∣ 4 x - 10 ∣ \geq 3

- 14 + 6 b + 7 - 2 b = 1 + 5 b

What are the solutions to the equation 80x^2+23x-9=0 ?
The solutions to the equation 80x^2+23x-9=0 are x=(-23+sqrt(3409))/(160),x=(-23-sqrt(3409))/(160)
Find the zeros of 80x^2+23x-9=0
The zeros of 80x^2+23x-9=0 are x=(-23+sqrt(3409))/(160),x=(-23-sqrt(3409))/(160)