What are the solutions to the equation 3x^2-2x+1=7x+1 ?

The solutions to the equation 3x^2-2x+1=7x+1 are x=3,x=0

Find the zeros of 3x^2-2x+1=7x+1

The zeros of 3x^2-2x+1=7x+1 are x=3,x=0

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3 x^{2} - 2 x + 1 = 7 x + 1

x = 3, x = 0

Solution steps

3 x^{2} - 2 x + 1 = 7 x + 1

Move

1

to the left side

3 x^{2} - 2 x = 7 x

Move

7 x

to the left side

3 x^{2} - 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 9)^{2} - 4 \cdot 3 \cdot 0 = 9

x_{1, 2} = \frac{- ( - 9 ) \pm 9}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 9}{2 \cdot 3}, x_{2} = \frac{- ( - 9 ) - 9}{2 \cdot 3}

x = \frac{- ( - 9 ) + 9}{2 \cdot 3} : 3

x = \frac{- ( - 9 ) - 9}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

3 - 7 x \leq 5 x + 15

lo g_{5} (1) = x

\frac{2 π}{\frac{5}{4}}

2 x + 3 = 5 x - 5

∣ 5 x + 2 ∣ + 1 > 8

What are the solutions to the equation 3x^2-2x+1=7x+1 ?
The solutions to the equation 3x^2-2x+1=7x+1 are x=3,x=0
Find the zeros of 3x^2-2x+1=7x+1
The zeros of 3x^2-2x+1=7x+1 are x=3,x=0