What are the solutions to the equation 1/16 =x^2 ?

The solutions to the equation 1/16 =x^2 are x= 1/4 ,x=-1/4

Find the zeros of 1/16 =x^2

The zeros of 1/16 =x^2 are x= 1/4 ,x=-1/4

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\frac{1}{16} = x^{2}

x = \frac{1}{4}, x = - \frac{1}{4}

Solution steps

\frac{1}{16} = x^{2}

Switch sides

x^{2} = \frac{1}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{16}, x = - \frac{1}{16}

\frac{1}{16} = \frac{1}{4}

- \frac{1}{16} = - \frac{1}{4}

x = \frac{1}{4}, x = - \frac{1}{4}

2 \cdot 2^{\frac{2}{3}}

\frac{5}{3} - 3

∣ 2 x + 1 ∣ = ∣ - 3 x + 1 ∣

5 (x + 3)^{2} - 5 y^{2}

27 x^{2} - 729 = 0

What are the solutions to the equation 1/16 =x^2 ?
The solutions to the equation 1/16 =x^2 are x= 1/4 ,x=-1/4
Find the zeros of 1/16 =x^2
The zeros of 1/16 =x^2 are x= 1/4 ,x=-1/4