|2x-3|<3

Solution

∣ 2 x - 3 ∣ < 3

0 < x < 3

Interval Notation

(0, 3)

Solution steps

∣ 2 x - 3 ∣ < 3

Apply absolute rule: If

∣ u ∣ < a, a > 0

then

- a < u < a

- 3 < 2 x - 3 < 3

2 x - 3 > - 3 and 2 x - 3 < 3

x > 0 and x < 3

Merge Overlapping Intervals

0 < x < 3

2 x^{5} - 10 x^{4} + 7 x^{3} + 13 x^{2} + 3 x + 9

\frac{2}{7 a} + \frac{3}{5 a}

\frac{25 !}{5 ! ( 25 - 5 ) !}

10 - 3 x + 10 x - 7 = 5 x - 5 + 2 x + 8

- 4 n + 11 < - 9