What are the solutions to the equation 10x^2-21x-10=0 ?

The solutions to the equation 10x^2-21x-10=0 are x= 5/2 ,x=-2/5

Find the zeros of 10x^2-21x-10=0

The zeros of 10x^2-21x-10=0 are x= 5/2 ,x=-2/5

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10 x^{2} - 21 x - 10 = 0

x = \frac{5}{2}, x = - \frac{2}{5}

Decimal Notation

x = 2.5, x = - 0.4

Solution steps

10 x^{2} - 21 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 10 ( - 10 )}{2 \cdot 10}

(- 21)^{2} - 4 \cdot 10 (- 10) = 29

x_{1, 2} = \frac{- ( - 21 ) \pm 29}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 29}{2 \cdot 10}, x_{2} = \frac{- ( - 21 ) - 29}{2 \cdot 10}

x = \frac{- ( - 21 ) + 29}{2 \cdot 10} : \frac{5}{2}

x = \frac{- ( - 21 ) - 29}{2 \cdot 10} : - \frac{2}{5}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{2}{5}

8 - ∣ 3 x + 6 ∣ = 5

- x^{5} + 6 x^{3} - 9 x

- n^{2} - 5 n + 14

(- \frac{3}{2})^{2} + 4 (- \frac{3}{2})

3 x + 30 = 0

What are the solutions to the equation 10x^2-21x-10=0 ?
The solutions to the equation 10x^2-21x-10=0 are x= 5/2 ,x=-2/5
Find the zeros of 10x^2-21x-10=0
The zeros of 10x^2-21x-10=0 are x= 5/2 ,x=-2/5