What are the solutions to the equation (x-4)^2=-4 ?

The solutions to the equation (x-4)^2=-4 are x=2i+4,x=-2i+4

Find the zeros of (x-4)^2=-4

The zeros of (x-4)^2=-4 are x=2i+4,x=-2i+4

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(x - 4)^{2} = - 4

x = 2 i + 4, x = - 2 i + 4

Solution steps

(x - 4)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = - 4 : x = 2 i + 4

Solve

x - 4 = - - 4 : x = - 2 i + 4

The solutions to the quadratic equation are:

x = 2 i + 4, x = - 2 i + 4

3 x^{2} - 4 x < 2 x^{2} + 21

\frac{240 - 80 x}{3} \cdot 0.22 = \frac{80 x}{3} \cdot 0.21

16 x^{2} = 56 x - 51

6 x (x - 4)^{4} + 12 x^{2} (x - 4)^{3}

4 - 2 n = 3 (7 + 2 n) - 1

What are the solutions to the equation (x-4)^2=-4 ?
The solutions to the equation (x-4)^2=-4 are x=2i+4,x=-2i+4
Find the zeros of (x-4)^2=-4
The zeros of (x-4)^2=-4 are x=2i+4,x=-2i+4