What are the solutions to the equation x^2+pix+2=0 ?

The solutions to the equation x^2+pix+2=0 are x=(-pi+sqrt(pi^2-8))/2 ,x=(-pi-sqrt(pi^2-8))/2

Find the zeros of x^2+pix+2=0

The zeros of x^2+pix+2=0 are x=(-pi+sqrt(pi^2-8))/2 ,x=(-pi-sqrt(pi^2-8))/2

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x^{2} + π x + 2 = 0

x = \frac{- π + π ^{2} - 8}{2}, x = \frac{- π - π ^{2} - 8}{2}

Decimal Notation

x = - 0.88712 \dots, x = - 2.25446 \dots

Solution steps

x^{2} + π x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- π \pm π ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

π^{2} - 4 \cdot 1 \cdot 2 = π^{2} - 8

x_{1, 2} = \frac{- π \pm π ^{2} - 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- π + π ^{2} - 8}{2 \cdot 1}, x_{2} = \frac{- π - π ^{2} - 8}{2 \cdot 1}

x = \frac{- π + π ^{2} - 8}{2 \cdot 1} : \frac{- π + π ^{2} - 8}{2}

x = \frac{- π - π ^{2} - 8}{2 \cdot 1} : \frac{- π - π ^{2} - 8}{2}

The solutions to the quadratic equation are:

x = \frac{- π + π ^{2} - 8}{2}, x = \frac{- π - π ^{2} - 8}{2}

- 5 - 5 m < - 6 (5 + 5 m)

\frac{( 1 + i )}{( 2 - 5 i )}

x^{2} + 20 x y + 75 y^{2}

\frac{1}{3} (6 x - 15) = \frac{1}{2} (10 x - 4)

\frac{x - y}{x - y} - x

What are the solutions to the equation x^2+pix+2=0 ?
The solutions to the equation x^2+pix+2=0 are x=(-pi+sqrt(pi^2-8))/2 ,x=(-pi-sqrt(pi^2-8))/2
Find the zeros of x^2+pix+2=0
The zeros of x^2+pix+2=0 are x=(-pi+sqrt(pi^2-8))/2 ,x=(-pi-sqrt(pi^2-8))/2