What are the solutions to the equation m^2-6m=49 ?

The solutions to the equation m^2-6m=49 are m=3+sqrt(58),m=3-sqrt(58)

Find the zeros of m^2-6m=49

The zeros of m^2-6m=49 are m=3+sqrt(58),m=3-sqrt(58)

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m^{2} - 6 m = 49

m = 3 + 58, m = 3 - 58

Decimal Notation

m = 10.61577 \dots, m = - 4.61577 \dots

Solution steps

m^{2} - 6 m = 49

Move

49

to the left side

m^{2} - 6 m - 49 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 49 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 49) = 258

m_{1, 2} = \frac{- ( - 6 ) \pm 2 58}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 6 ) + 2 58}{2 \cdot 1}, m_{2} = \frac{- ( - 6 ) - 2 58}{2 \cdot 1}

m = \frac{- ( - 6 ) + 2 58}{2 \cdot 1} : 3 + 58

m = \frac{- ( - 6 ) - 2 58}{2 \cdot 1} : 3 - 58

The solutions to the quadratic equation are:

m = 3 + 58, m = 3 - 58

\frac{1}{2} x + \frac{1}{4} \geq \frac{3}{2} x + \frac{3}{4}

\frac{3 x ^{- 1} + y x ^{- 3}}{x ^{- 1} y ^{2}}

∣ x - 3 ∣ = ∣ 2 x + 3 ∣

12 x^{2} - 7 x + 1

3 (\frac{5}{7})

What are the solutions to the equation m^2-6m=49 ?
The solutions to the equation m^2-6m=49 are m=3+sqrt(58),m=3-sqrt(58)
Find the zeros of m^2-6m=49
The zeros of m^2-6m=49 are m=3+sqrt(58),m=3-sqrt(58)