What are the solutions to the equation (x-1)(x+8)=5x ?

The solutions to the equation (x-1)(x+8)=5x are x=2,x=-4

Find the zeros of (x-1)(x+8)=5x

The zeros of (x-1)(x+8)=5x are x=2,x=-4

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(x - 1) (x + 8) = 5 x

x = 2, x = - 4

Solution steps

(x - 1) (x + 8) = 5 x

Expand

(x - 1) (x + 8) : x^{2} + 7 x - 8

x^{2} + 7 x - 8 = 5 x

Move

5 x

to the left side

x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 8) = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 \cdot 1}, x_{2} = \frac{- 2 - 6}{2 \cdot 1}

x = \frac{- 2 + 6}{2 \cdot 1} : 2

x = \frac{- 2 - 6}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

x^{22}

∣ 8 y - 5 ∣ \geq 10

5 (x + 9)^{2} = 60

6 - 13 b - 5 b^{2} < 0

∣ 8 - 3 x ∣ - 3 = - 2

What are the solutions to the equation (x-1)(x+8)=5x ?
The solutions to the equation (x-1)(x+8)=5x are x=2,x=-4
Find the zeros of (x-1)(x+8)=5x
The zeros of (x-1)(x+8)=5x are x=2,x=-4