The solution to x-3x^2>= 0 is 0<= x<= 1/3

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x-3x^2>= 0

Solution

x - 3 x^{2} \geq 0

0 \leq x \leq \frac{1}{3}

Interval Notation

[0, \frac{1}{3}]

Decimal Notation

0 \leq x \leq 0.33333 \dots

Solution steps

x - 3 x^{2} \geq 0

Factor

x - 3 x^{2} : - x (3 x - 1)

- x (3 x - 1) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- x (3 x - 1)) (- 1) \leq 0 \cdot (- 1)

Simplify

x (3 x - 1) \leq 0

Identify the intervals

0 \leq x \leq \frac{1}{3}

250 x^{4} + 128 x

- 3 + x < 37

x^{2} - 5 = (x + 5) (2 x - 1)

9^{0}

6 x^{2} - 16 = 5 x^{2} - 6 x