|7-8x|>16

Solution

∣ 7 - 8 x ∣ > 16

x < - \frac{9}{8} or x > \frac{23}{8}

Interval Notation

(- \infty, - \frac{9}{8}) \cup (\frac{23}{8}, \infty)

Decimal Notation

x < - 1.125 or x > 2.875

Solution steps

∣ 7 - 8 x ∣ > 16

Apply absolute rule: If

∣ u ∣ > a, a > 0

then

u < - a

u > a

7 - 8 x < - 16 or 7 - 8 x > 16

7 - 8 x < - 16 or 7 - 8 x > 16

x < - \frac{9}{8} or x > \frac{23}{8}

6 h^{2} + 5 h - 6

x^{2} = 4 x + 21

5 a (x - y) + 10 a^{2} x y - 10 a^{2} y^{2}

(1 + \frac{0.05}{12})^{12}