What are the solutions to the equation 3x^2+2x=0 ?

The solutions to the equation 3x^2+2x=0 are x=0,x=-2/3

Find the zeros of 3x^2+2x=0

The zeros of 3x^2+2x=0 are x=0,x=-2/3

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3 x^{2} + 2 x = 0

x = 0, x = - \frac{2}{3}

Decimal Notation

x = 0, x = - 0.66666 \dots

Solution steps

3 x^{2} + 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

2^{2} - 4 \cdot 3 \cdot 0 = 2

x_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 2}{2 \cdot 3}, x_{2} = \frac{- 2 - 2}{2 \cdot 3}

x = \frac{- 2 + 2}{2 \cdot 3} : 0

x = \frac{- 2 - 2}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{2}{3}

∣ x + 4 ∣ \leq 6

x - 18.2 = - 16.7

(\frac{y}{x})^{3}

(x - 3) (x + 6) = (x - 4) (x - 5)

3 ∣ 2 x - 7 ∣ = 9

What are the solutions to the equation 3x^2+2x=0 ?
The solutions to the equation 3x^2+2x=0 are x=0,x=-2/3
Find the zeros of 3x^2+2x=0
The zeros of 3x^2+2x=0 are x=0,x=-2/3