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Popular >

-x^2+x+6<= 0

Solution

- x^{2} + x + 6 \leq 0

Solution

x \leq - 2 or x \geq 3

+1

Interval Notation

(- \infty, - 2] \cup [3, \infty)

Solution steps

- x^{2} + x + 6 \leq 0

Factor

- x^{2} + x + 6 : - (x + 2) (x - 3)

- (x + 2) (x - 3) \leq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x + 2) (x - 3)) (- 1) \geq 0 \cdot (- 1)

Simplify

(x + 2) (x - 3) \geq 0

Identify the intervals

x \leq - 2 or x \geq 3

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\frac{11 π}{6} - π

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\frac{18 x ^{2} y ^{3} z ^{2}}{30 x ^{2} y z ^{4}}

Frequently Asked Questions (FAQ)

What is -x^2+x+6<= 0 ?
The solution to -x^2+x+6<= 0 is x<=-2\lor x>= 3