What is ((x+2)(-x+2))/(2x+4)<= 0 ?

The solution to ((x+2)(-x+2))/(2x+4) = 2

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((x+2)(-x+2))/(2x+4)<= 0

\frac{( x + 2 ) ( - x + 2 )}{2 x + 4} \leq 0

x \geq 2

Interval Notation

[2, \infty)

Solution steps

\frac{( x + 2 ) ( - x + 2 )}{2 x + 4} \leq 0

Factor

\frac{( x + 2 ) ( - x + 2 )}{2 x + 4} : \frac{( x + 2 ) ( - x + 2 )}{2 ( x + 2 )}

\frac{( x + 2 ) ( - x + 2 )}{2 ( x + 2 )} \leq 0

Multiply both sides by

2

\frac{2 ( x + 2 ) ( - x + 2 )}{2 ( x + 2 )} \leq 0 \cdot 2

Simplify

- x + 2 \leq 0

Identify the intervals

x \geq 2

5 z^{2} + 11 z + 2

4 x - 2 (x + 1) \leq 0

x^{2} + 5 x + 100 = 0

x^{2} - 4 x = - 2

x^{3} - 8 x^{2} + 7 x - 56

What is ((x+2)(-x+2))/(2x+4)<= 0 ?
The solution to ((x+2)(-x+2))/(2x+4)<= 0 is x>= 2