What are the solutions to the equation 3x^2+4x-3=0 ?

The solutions to the equation 3x^2+4x-3=0 are x=(-2+sqrt(13))/3 ,x=-(2+sqrt(13))/3

Find the zeros of 3x^2+4x-3=0

The zeros of 3x^2+4x-3=0 are x=(-2+sqrt(13))/3 ,x=-(2+sqrt(13))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 4 x - 3 = 0

x = \frac{- 2 + 13}{3}, x = - \frac{2 + 13}{3}

Decimal Notation

x = 0.53518 \dots, x = - 1.86851 \dots

Solution steps

3 x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 3) = 213

x_{1, 2} = \frac{- 4 \pm 2 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2 13}{2 \cdot 3}, x_{2} = \frac{- 4 - 2 13}{2 \cdot 3}

x = \frac{- 4 + 2 13}{2 \cdot 3} : \frac{- 2 + 13}{3}

x = \frac{- 4 - 2 13}{2 \cdot 3} : - \frac{2 + 13}{3}

The solutions to the quadratic equation are:

x = \frac{- 2 + 13}{3}, x = - \frac{2 + 13}{3}

4 x^{2} + 48 x + 128 = 0

\frac{1}{2} - x < 5

4 x^{2} - 3 x^{2} = 0

\frac{50}{4}

2 x^{2} - 4

What are the solutions to the equation 3x^2+4x-3=0 ?
The solutions to the equation 3x^2+4x-3=0 are x=(-2+sqrt(13))/3 ,x=-(2+sqrt(13))/3
Find the zeros of 3x^2+4x-3=0
The zeros of 3x^2+4x-3=0 are x=(-2+sqrt(13))/3 ,x=-(2+sqrt(13))/3