What is (10x+4y}{32}+\frac{-3x+y)/8 ?

The solution to (10x+4y}{32}+\frac{-3x+y)/8 is (-x+4y)/(16)

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simplify (10x+4y}{32}+\frac{-3x+y)/8

simplify

\frac{10 x + 4 y}{32} + \frac{- 3 x + y}{8}

\frac{- x + 4 y}{16}

Solution steps

\frac{10 x + 4 y}{32} + \frac{- 3 x + y}{8}

Cancel

\frac{10 x + 4 y}{32} : \frac{5 x + 2 y}{16}

= \frac{5 x + 2 y}{16} + \frac{- 3 x + y}{8}

Simplify

\frac{5 x + 2 y}{16} + \frac{- 3 x + y}{8} : \frac{5 x + 2 y + ( - 3 x + y ) \cdot 2}{16}

= \frac{5 x + 2 y + ( - 3 x + y ) \cdot 2}{16}

Simplify

5 x + 2 y + (- 3 x + y) \cdot 2 : - x + 4 y

= \frac{- x + 4 y}{16}

x^{3} < 49 x

\frac{9}{- 10 - 5 i}

\frac{9}{3} - \frac{6}{10}

x^{4} - 4 x^{3} - x^{2} + 4 x = 0

What is (10x+4y}{32}+\frac{-3x+y)/8 ?
The solution to (10x+4y}{32}+\frac{-3x+y)/8 is (-x+4y)/(16)