What is 1/x+1/(x+1)< 2/(x+8) ?

The solution to 1/x+1/(x+1)< 2/(x+8) is -8<x<-1\lor-8/15 <x<0

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1/x+1/(x+1)< 2/(x+8)

\frac{1}{x} + \frac{1}{x + 1} < \frac{2}{x + 8}

- 8 < x < - 1 or - \frac{8}{15} < x < 0

Interval Notation

(- 8, - 1) \cup (- \frac{8}{15}, 0)

Decimal Notation

- 8 < x < - 1 or - 0.53333 \dots < x < 0

Solution steps

\frac{1}{x} + \frac{1}{x + 1} < \frac{2}{x + 8}

Rewrite in standard form

\frac{15 x + 8}{x ( x + 1 ) ( x + 8 )} < 0

Identify the intervals

- 8 < x < - 1 or - \frac{8}{15} < x < 0

2 w y + 3 y x - 8 w z - 12 z x

- 2 b^{2} + 5 ab + 7 a^{2}

2 4^{\frac{1}{2}}

18 r^{3} t^{2} + 12 r^{2} t^{2} - 6 r^{2} t

- 61 = 3 m - 4

What is 1/x+1/(x+1)< 2/(x+8) ?
The solution to 1/x+1/(x+1)< 2/(x+8) is -8<x<-1\lor-8/15 <x<0