What are the solutions to the equation 2x^2+9x-8=0 ?

The solutions to the equation 2x^2+9x-8=0 are x=(-9+sqrt(145))/4 ,x=(-9-sqrt(145))/4

Find the zeros of 2x^2+9x-8=0

The zeros of 2x^2+9x-8=0 are x=(-9+sqrt(145))/4 ,x=(-9-sqrt(145))/4

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2 x^{2} + 9 x - 8 = 0

x = \frac{- 9 + 145}{4}, x = \frac{- 9 - 145}{4}

Decimal Notation

x = 0.76039 \dots, x = - 5.26039 \dots

Solution steps

2 x^{2} + 9 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

9^{2} - 4 \cdot 2 (- 8) = 145

x_{1, 2} = \frac{- 9 \pm 145}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 145}{2 \cdot 2}, x_{2} = \frac{- 9 - 145}{2 \cdot 2}

x = \frac{- 9 + 145}{2 \cdot 2} : \frac{- 9 + 145}{4}

x = \frac{- 9 - 145}{2 \cdot 2} : \frac{- 9 - 145}{4}

The solutions to the quadratic equation are:

x = \frac{- 9 + 145}{4}, x = \frac{- 9 - 145}{4}

2 x^{2} - 40 x + 200

n^{2} + 3 n - 28

\frac{x}{y} \cdot \frac{1}{2}

2 x^{2} + 28 x - 480 = 0

a^{2} + 14 a + 63 = 8

What are the solutions to the equation 2x^2+9x-8=0 ?
The solutions to the equation 2x^2+9x-8=0 are x=(-9+sqrt(145))/4 ,x=(-9-sqrt(145))/4
Find the zeros of 2x^2+9x-8=0
The zeros of 2x^2+9x-8=0 are x=(-9+sqrt(145))/4 ,x=(-9-sqrt(145))/4