What are the solutions to the equation 2x^2-12x+25=0 ?

The solutions to the equation 2x^2-12x+25=0 are x=3+isqrt(7/2),x=3-isqrt(7/2)

Find the zeros of 2x^2-12x+25=0

The zeros of 2x^2-12x+25=0 are x=3+isqrt(7/2),x=3-isqrt(7/2)

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2 x^{2} - 12 x + 25 = 0

x = 3 + i \frac{7}{2}, x = 3 - i \frac{7}{2}

Solution steps

2 x^{2} - 12 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 \cdot 25}{2 \cdot 2}

Simplify

(- 12)^{2} - 4 \cdot 2 \cdot 25 : 214 i

x_{1, 2} = \frac{- ( - 12 ) \pm 2 14 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 14 i}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 2 14 i}{2 \cdot 2}

x = \frac{- ( - 12 ) + 2 14 i}{2 \cdot 2} : 3 + i \frac{7}{2}

x = \frac{- ( - 12 ) - 2 14 i}{2 \cdot 2} : 3 - i \frac{7}{2}

The solutions to the quadratic equation are:

x = 3 + i \frac{7}{2}, x = 3 - i \frac{7}{2}

2 x^{2} = - 8 x - 5

(u^{- \frac{1}{2}})^{3}

6 x^{2} + 8 x + 2 = 0

(v^{7})^{\frac{1}{2}}

(1334.662 \cdot 2) + 228 - c = 296.1 \cdot 2

What are the solutions to the equation 2x^2-12x+25=0 ?
The solutions to the equation 2x^2-12x+25=0 are x=3+isqrt(7/2),x=3-isqrt(7/2)
Find the zeros of 2x^2-12x+25=0
The zeros of 2x^2-12x+25=0 are x=3+isqrt(7/2),x=3-isqrt(7/2)