What are the solutions to the equation (q+3)^2=4 ?

The solutions to the equation (q+3)^2=4 are q=-1,q=-5

Find the zeros of (q+3)^2=4

The zeros of (q+3)^2=4 are q=-1,q=-5

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(q + 3)^{2} = 4

q = - 1, q = - 5

Solution steps

(q + 3)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

q + 3 = 4 : q = - 1

Solve

q + 3 = - 4 : q = - 5

The solutions to the quadratic equation are:

q = - 1, q = - 5

2 x + 6 = 5 x

- 2

14 = x^{2} - 5 x

∣ 2 x + 9 ∣ \leq 8

\frac{6 - 3 x}{4} = - 3

What are the solutions to the equation (q+3)^2=4 ?
The solutions to the equation (q+3)^2=4 are q=-1,q=-5
Find the zeros of (q+3)^2=4
The zeros of (q+3)^2=4 are q=-1,q=-5