What are the solutions to the equation 64x^2-1=0 ?

The solutions to the equation 64x^2-1=0 are x= 1/8 ,x=-1/8

Find the zeros of 64x^2-1=0

The zeros of 64x^2-1=0 are x= 1/8 ,x=-1/8

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64 x^{2} - 1 = 0

x = \frac{1}{8}, x = - \frac{1}{8}

Decimal

x = 0.125, x = - 0.125

Solution steps

64 x^{2} - 1 = 0

Move

1

to the right side

64 x^{2} = 1

Divide both sides by

64

x^{2} = \frac{1}{64}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{64}, x = - \frac{1}{64}

\frac{1}{64} = \frac{1}{8}

- \frac{1}{64} = - \frac{1}{8}

x = \frac{1}{8}, x = - \frac{1}{8}

- 4 s \geq - 36

x + \frac{8}{7} > \frac{7}{6}

2 (6 d + 3) = 18 - 3 (16 - 3 d)

- x^{3} + 2 x^{2} + 15 x

5 x^{2} - 5 x = 1

What are the solutions to the equation 64x^2-1=0 ?
The solutions to the equation 64x^2-1=0 are x= 1/8 ,x=-1/8
Find the zeros of 64x^2-1=0
The zeros of 64x^2-1=0 are x= 1/8 ,x=-1/8