What are the solutions to the equation 2x^2+3x=0 ?

The solutions to the equation 2x^2+3x=0 are x=0,x=-3/2

Find the zeros of 2x^2+3x=0

The zeros of 2x^2+3x=0 are x=0,x=-3/2

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2 x^{2} + 3 x = 0

x = 0, x = - \frac{3}{2}

Decimal Notation

x = 0, x = - 1.5

Solution steps

2 x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

3^{2} - 4 \cdot 2 \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 \cdot 2}, x_{2} = \frac{- 3 - 3}{2 \cdot 2}

x = \frac{- 3 + 3}{2 \cdot 2} : 0

x = \frac{- 3 - 3}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{3}{2}

\frac{m ^{2} - 25}{m - 5}

- 4 x < 24

5 c + 3 \geq 6 c - 8

\frac{x - 18}{8} \geq \frac{x - 9}{12} + \frac{1}{24}

5.5 x - 0.004 x^{2} = 256 + 0.65 x

What are the solutions to the equation 2x^2+3x=0 ?
The solutions to the equation 2x^2+3x=0 are x=0,x=-3/2
Find the zeros of 2x^2+3x=0
The zeros of 2x^2+3x=0 are x=0,x=-3/2