What are the solutions to the equation -2=3x^2-x-2 ?

The solutions to the equation -2=3x^2-x-2 are x= 1/3 ,x=0

Find the zeros of -2=3x^2-x-2

The zeros of -2=3x^2-x-2 are x= 1/3 ,x=0

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- 2 = 3 x^{2} - x - 2

x = \frac{1}{3}, x = 0

Decimal Notation

x = 0.33333 \dots, x = 0

Solution steps

- 2 = 3 x^{2} - x - 2

Switch sides

3 x^{2} - x - 2 = - 2

Move

2

to the left side

3 x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 3}

x = \frac{- ( - 1 ) + 1}{2 \cdot 3} : \frac{1}{3}

x = \frac{- ( - 1 ) - 1}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = 0

0 \leq 2 x - 6 \leq 4

y^{2} - 25 x^{2}

2 x - x 5 = 9

4 x^{2} - 18 x + 8 = 0

16 m^{4} - 1

What are the solutions to the equation -2=3x^2-x-2 ?
The solutions to the equation -2=3x^2-x-2 are x= 1/3 ,x=0
Find the zeros of -2=3x^2-x-2
The zeros of -2=3x^2-x-2 are x= 1/3 ,x=0